document.write( "Question 383934: I have an equation -36wx^2-114wx-70w that needs to be factored completely, i get to 2w(-18x^2-57x-35) but then am not able to simplify it any more, and was just curious if thats the final result? \r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #271865 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There is nothing wrong about factoring out 2w and getting: \n" ); document.write( " \n" ); document.write( "But as you see, the squared term has a negative coefficient. This makes subsequent factoring a little more difficult. So in situations like this I prefer to factor out the negative of the GCF, -2w, giving us: \n" ); document.write( " \n" ); document.write( "Next we try to factor \n" ); document.write( "(18x+35)(x+1) \n" ); document.write( "(18x+1)(x+35) \n" ); document.write( "(9x-1)(x-35) \n" ); document.write( "(6x+5)(3x+7) \n" ); document.write( "etc. \n" ); document.write( "For 18 the factors are 1*18, 2*9 and 3*6. For 35 the factors are 35*1 and 7*5. The total number of combinations is: 3*2*2*2 = 24. (3 for 3 pairs of factors of 18, 2 for two pairs of factors of 35, 2 to include the negative factors and the last 2 for swapping the order [(18x+35)(x+1) and (18x+1)(x+35) are different and count as two of the combinations.] \n" ); document.write( "With 24 possible combinations is can take a while to find the right one, if it exists! After all, this trinomial may not factor! \n" ); document.write( "For expressions like this where there is a significant number of possible combinations here's a \"trick\" you can use. (It's totally valid Math, not some magic your teacher would not like to see you use.) It involves using the Quadratic Formula is a way you may have not seen before. \n" ); document.write( "The Quadratic Formula: \n" ); document.write( " \n" ); document.write( "The part of the formula inside the square root, \n" ); document.write( "If the value of the discriminant is a perfect square the trinomial will factor. If the value of the discriminant is a not perfect square the trinomial will not factor. Let's try this on your quadratic expression. Your \"b\" is 57, \"a\" is 18, and \"c\" is 35: \n" ); document.write( " \n" ); document.write( "which simplifies as follows: \n" ); document.write( "3249 - 4(18)(35) \n" ); document.write( "3249 - 2520 \n" ); document.write( "729 \n" ); document.write( "Your discriminant is 729. 729 is a perfect square ( \n" ); document.write( " \n" ); document.write( "We can also use the Quadratic Formula to find the right combination! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In long form this is: \n" ); document.write( " \n" ); document.write( "These simplify: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This makes the factors: \n" ); document.write( "(6x - (-5))(3x - (-7)) \n" ); document.write( "Note that the factors will have a minus in the middle and note where the numerator and denominator of each fraction goes. These factors simplify to \n" ); document.write( "(6x + 5)(3x + 7) \n" ); document.write( "This makes our final answer: \n" ); document.write( " \n" ); document.write( "So we can factor trinomials by any of the following methods:
\n" ); document.write( "When I factor trinomials, the number of combinations determines which approach I use. If the number of combinations is fairly low or if the right combination is \"obvious\" to me then I use the first approach. Otherwise I use the discriminant to determine if it is worth continuing. \n" ); document.write( "In summary, you don't have to learn how to use the Quadratic Formula to factor. But it can save you a lot of time when there are a significant number of combinations to try. \n" ); document.write( " |