document.write( "Question 42056: A tourist bus leaves Townsville and heads North. It travels at an average speed of 50 km/h. It does not stop until it reaches the small little known settlement of Goanna Creek. A second tourist bus leaves Townsville 2 hours later than the first and travels at an average speed of 70 km/h. The second bus arrives at Goanna Creek at the same time as the first bus. How far is Goanna Creek from Townsville? \n" ); document.write( "
Algebra.Com's Answer #27186 by psbhowmick(878)\"\" \"About 
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Let the distance between Townsville and Goanna Creek = x km.\r
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\n" ); document.write( "\n" ); document.write( "For first bus:
\n" ); document.write( "Distance to be traveled = x km.
\n" ); document.write( "Average speed = 50 km/h.
\n" ); document.write( "Therefore, time taken = \"DISTANCE%2FSPEED\" = \"x%2F50\" hours.\r
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\n" ); document.write( "\n" ); document.write( "For second bus:
\n" ); document.write( "Distance to be traveled = x km.
\n" ); document.write( "Average speed = 70 km/h.
\n" ); document.write( "Therefore, time taken = \"DISTANCE%2FSPEED\" = \"x%2F70\" hours.\r
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\n" ); document.write( "\n" ); document.write( "The second bus started 2 hrs. after the departure of the first bus but both reached the destination at the same time.
\n" ); document.write( "So, the second bus takes 2 hr. less time than the first bus to complete the journey.\r
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\n" ); document.write( "\n" ); document.write( "So we can write,
\n" ); document.write( "(Time taken by second bus in hrs.) = (Time taken by first bus in hrs.) - 2
\n" ); document.write( "or \"x%2F70+=+x%2F50+-+2\"
\n" ); document.write( "or \"x%2F50+-+x%2F70+=+2\"
\n" ); document.write( "or \"%2870x-50x%29%2F%2850%2A70%29+=+2\"
\n" ); document.write( "or \"20x%2F%2870%2A50%29+=+2\"
\n" ); document.write( "or \"x%2F%287%2A50%29+=+1\"
\n" ); document.write( "or x = 350\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, the reqd. distance is 350 km.
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