document.write( "Question 383943: log square root 100y in expanded form \n" ); document.write( "
Algebra.Com's Answer #271854 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%28sqrt%28100y%29%29%29\"
\n" ); document.write( "To start we need to remember that a square root is the same as an exponent of 1/2. So we can rewrite your expression as:
\n" ); document.write( "\"log%28%28%28100y%29%5E%281%2F2%29%29%29\"
\n" ); document.write( "Next we can use a property of logarithms, \"log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29\", to move the exponent of the argument out in front:
\n" ); document.write( "\"%281%2F2%29log%28%28100y%29%29\"
\n" ); document.write( "Next we can use another property of logarithms, \"log%28a%2C+%28p%2Aq%29%29+=+log%28a%2C+%28p%29%29+%2B+log%28a%2C+%28q%29%29\", to rewrite the log of the product as the sum of the logs of the factors:
\n" ); document.write( "\"%281%2F2%29%28log%28%28100%29%29%2Blog%28%28y%29%29%29\"
\n" ); document.write( "Note the use of parentheses. It is an extremely good habit to use parentheses when substituting. In this case it helps us know that the Distributive Property applies with the 1/2:
\n" ); document.write( "\"%281%2F2%29log%28%28100%29%29%2B%281%2F2%29log%28%28y%29%29\"
\n" ); document.write( "Since the base of log is 10 and since \"100+=+10%5E2\", \"log%28%28100%29%29+=+2\":
\n" ); document.write( "\"%281%2F2%29%282%29%2B%281%2F2%29log%28%28y%29%29\"
\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"1%2B%281%2F2%29log%28%28y%29%29\"
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