document.write( "Question 384030: v \n" ); document.write( "
Algebra.Com's Answer #271852 by mananth(16946)\"\" \"About 
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the present age of father is 4times of his son. 10 years before the age of father was 9times of his son age.find out their present age?
\n" ); document.write( "..
\n" ); document.write( "son= x years
\n" ); document.write( "father = 4x
\n" ); document.write( "..
\n" ); document.write( "10 years ago
\n" ); document.write( "son = x-10
\n" ); document.write( "father = 4x-10
\n" ); document.write( "...
\n" ); document.write( "4x-10=9(x-10)
\n" ); document.write( "4x-10=9x-90
\n" ); document.write( "4x-9x=-90+10
\n" ); document.write( "-5x=-80
\n" ); document.write( "/-5
\n" ); document.write( "x=16 son's age now
\n" ); document.write( "father's age = 4x = 4*16 = 64 years
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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