document.write( "Question 384060: A man invests $5000 in two different accounts. The first account has a 5% annual interest rate
\n" ); document.write( "and the second account has a 3% annual interest rate. If he receives $212.50 in interest at the
\n" ); document.write( "end of the year, how much money did he put into each account?
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Algebra.Com's Answer #271850 by mananth(16946)\"\" \"About 
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A man invests $5000 in two different accounts. The first account has a 5% annual interest rate
\n" ); document.write( "and the second account has a 3% annual interest rate. If he receives $212.50 in interest at the
\n" ); document.write( "end of the year, how much money did he put into each account?
\n" ); document.write( "..
\n" ); document.write( "5% -------------- $x
\n" ); document.write( "3%--------------- $y
\n" ); document.write( "..
\n" ); document.write( "x+y = 5000...................1
\n" ); document.write( "..
\n" ); document.write( "5x+3y=21250.................2
\n" ); document.write( "..
\n" ); document.write( "multiply (1) by -5
\n" ); document.write( "-5x-5y=-25000
\n" ); document.write( "add it to (2)
\n" ); document.write( "5x-5x+3y-5y=-25000+21250
\n" ); document.write( "-2y= -3750
\n" ); document.write( "/-2
\n" ); document.write( "y= $1,875 @ 3%
\n" ); document.write( "balance $3125 @ 5%
\n" ); document.write( "..
\n" ); document.write( "CHECK
\n" ); document.write( "(1875*3+3125*5)/100 = 212.50
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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