document.write( "Question 383979: Tom is 6 times as old as Todd. In 3 years Tom's age will be 33 years more than 2 times as old as Todd. How old is Tom? \n" ); document.write( "
Algebra.Com's Answer #271802 by mananth(16946)\"\" \"About 
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Tom is 6 times as old as Todd. In 3 years Tom's age will be 33 years more than 2 times as old as Todd. How old is Tom?
\n" ); document.write( "...
\n" ); document.write( "Todd be x years
\n" ); document.write( "Tom = 6x
\n" ); document.write( "..
\n" ); document.write( "after 3 years
\n" ); document.write( "Todd's age = x+3 years
\n" ); document.write( "Tom's age = 6x+3 years
\n" ); document.write( "..
\n" ); document.write( "6x+3 = 33+2(x+3)
\n" ); document.write( "6x+3=33+2x+6
\n" ); document.write( "6x+3=2x+39
\n" ); document.write( "-3 -3
\n" ); document.write( "6x=2x+36
\n" ); document.write( "-2x -2x
\n" ); document.write( "6x-2x=36
\n" ); document.write( "4x=36
\n" ); document.write( "/4
\n" ); document.write( "x= 9 years..... Todd's age
\n" ); document.write( "Tom's age = 6x = 6*9 = 54 years
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\n" ); document.write( "m.ananth@hotmail.ca
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