document.write( "Question 383979: Tom is 6 times as old as Todd. In 3 years Tom's age will be 33 years more than 2 times as old as Todd. How old is Tom? \n" ); document.write( "
Algebra.Com's Answer #271802 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Tom is 6 times as old as Todd. In 3 years Tom's age will be 33 years more than 2 times as old as Todd. How old is Tom? \n" ); document.write( "... \n" ); document.write( "Todd be x years \n" ); document.write( "Tom = 6x \n" ); document.write( ".. \n" ); document.write( "after 3 years \n" ); document.write( "Todd's age = x+3 years \n" ); document.write( "Tom's age = 6x+3 years \n" ); document.write( ".. \n" ); document.write( "6x+3 = 33+2(x+3) \n" ); document.write( "6x+3=33+2x+6 \n" ); document.write( "6x+3=2x+39 \n" ); document.write( "-3 -3 \n" ); document.write( "6x=2x+36 \n" ); document.write( "-2x -2x \n" ); document.write( "6x-2x=36 \n" ); document.write( "4x=36 \n" ); document.write( "/4 \n" ); document.write( "x= 9 years..... Todd's age \n" ); document.write( "Tom's age = 6x = 6*9 = 54 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |