document.write( "Question 383860: The sum of the squares of two consecutive odd negative integers is 290.Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #271752 by mananth(16946)\"\" \"About 
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let the numbers be x & x+2
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\n" ); document.write( "x^2+(x+2)^2=290
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\n" ); document.write( "x^2+x^2+4x+4=290
\n" ); document.write( "2x^2+4x+4=290
\n" ); document.write( "/2
\n" ); document.write( "x^2+2x+2-145=0
\n" ); document.write( "x^2+2x-143=0
\n" ); document.write( "x^2+13x-11x-143=0
\n" ); document.write( "x(x+13)-11(x+13)=0
\n" ); document.write( "(x+13)(x-11)=0
\n" ); document.write( "x=-13 OR 11
\n" ); document.write( "So x = -13
\n" ); document.write( "The numbers are -13, -11
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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