document.write( "Question 383849: let x be a random variable that represents the length of time it takes a student to write a term paper for Dr. Sugg's Stats class. After interviewing many students, it was found that x has an approximately normal distribution with mean ľ = 5.2 hours and standard deviation σ = 3.8 hours\r
\n" ); document.write( "\n" ); document.write( "Convert the following x intervals to standardized z intervals.
\n" ); document.write( "-2.0 ≤ x ≤ 2.9\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #271740 by robertb(5830) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"-2.0+%3C=+X+%3C=+2.9\"$ ;
\n" ); document.write( " $\"%28-2.0+-+5.2%29%2F3.8+%3C=+%28X+-+5.2%29%2F3.8+%3C=+%282.9+-+5.2%29%2F3.8\"$ ;
\n" ); document.write( " $\"-1.895+%3C=+Z+%3C=+-0.605\"$ . The formula for z-scores is $\"z+=+%28X-mu%29%2Fsigma\"$ . \n" ); document.write( "

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