document.write( "Question 383844: Diane is 3 times as old as sydney and Josh is 16 years younger than Diane. One year ago, Diane was twice the sum of syndent and Josh age. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #271733 by mananth(16946)\"\" \"About 
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Diane is 3 times as old as sydney and Josh is 16 years younger than Diane. One year ago, Diane was twice the sum of syndent and Josh age. Find their present ages.
\n" ); document.write( "..
\n" ); document.write( "let Sydney be x years old
\n" ); document.write( "Diana = 3x
\n" ); document.write( "Josh = 3x-16
\n" ); document.write( "..
\n" ); document.write( "1 year ago
\n" ); document.write( "sydney = x-1
\n" ); document.write( "Diana = 3x-1
\n" ); document.write( "Josh = 3x-16-1= 3x-17
\n" ); document.write( "..
\n" ); document.write( "3x-1= 2(x-1+3x-17)
\n" ); document.write( "3x-1=2(4x-18)
\n" ); document.write( "3x-1= 8x-36
\n" ); document.write( "8x-3x=36-1
\n" ); document.write( "5x=30
\n" ); document.write( "/5
\n" ); document.write( "x= 6 ... Sydney's age.
\n" ); document.write( "Diana = 18
\n" ); document.write( "Josh=38
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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