document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=383696>Question 383696</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi Will someone help please.\r<BR>\n" );
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document.write( "The d's are like curly d's not sure of the name or how to type?\r<BR>\n" );
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document.write( "Given f(x,y) = (x - y)/(x + y), evaluate df/dx and df/dy at the point (1,2).\r<BR>\n" );
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document.write( "Thanks in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271679 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the curly d's mean partial derivative. essentially u differentiate your f, first with respect to x, and then to y. by that i mean, when u differentiate with respect to x, treat y as a constant, and then the other way arnd for dy\r<BR>\n" );
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document.write( "example: let f(x,y)=x^2 + y^2. then df/dx = 2*x + 0. the y^2 becomes 0 since we treat it as a constant. similarly df/dy = 0+2y. <BR>\n" );
document.write( "hope this helps </SPAN>\n" );
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