document.write( "Question 383609: Hi
\n" ); document.write( " Stuck on this, can someone please help\r
\n" ); document.write( "\n" ); document.write( "The total surface area S of a closed cone of base radius r cm and perpendicular height h cm is given byS = pir^2 + pi r sqrt(r^2 + h^2). If r and h are each increasing at the rate of 0.25 cm s^-1, find the rate at which S is increasing at the instantwhen r = 3 and h = 4.\r
\n" ); document.write( "\n" ); document.write( " Thank You,
\n" ); document.write( "

Algebra.Com's Answer #271660 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"S+=+pi%2Ar%5E2+%2B+pi%2Ar%2Asqrt%28r%5E2+%2B+h%5E2%29\"
\n" ); document.write( "Differentiate with both \"r\" and \"h\" as variables.
\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "Substitute \"r=3\", \"h=4\", \"dr=dh=0.25\",
\n" ); document.write( "
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"dS=%283%2F2%29%2Api%2Bpi%2A3%2A%281%2F%282%2A5%29%29%2A%283%2F2%2B2%29%2B+pi%2A%285%2F4%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"dS=pi%2A%28%283%2F2%29%2B%2821%2F20%29%2B%285%2F4%29%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"dS=pi%2A%28%2830%2F20%29%2B%2821%2F20%29%2B%2825%2F20%29%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"dS=%2819%2F5%29%2Api\"\"cm%5E2%2Fs\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );