document.write( "Question 383323: Beer A is 6% alcohol, Beer B is 2% alcohol.
\n" ); document.write( "how many liters of beer A should be mixed in order to get 50 liters of mixture that is 3.2% alcohol.\r
\n" ); document.write( "\n" ); document.write( "solution A + B = 50 liter
\n" ); document.write( " 6%+2% = 3.2% alcohol
\n" ); document.write( " .06 + .02= 3.2
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\n" ); document.write( "\n" ); document.write( "I am stuck on this calculation, need to get one of the variables alone...like A but am not sure where to go from this point...
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Algebra.Com's Answer #271615 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Let A be the amount of beer A, B the amount of beer B.
\n" ); document.write( "1.\"A%2BB=50\"
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\n" ); document.write( "\"6A%2B2B=3.2%2850%29\"
\n" ); document.write( "\"6A%2B2B=160\"
\n" ); document.write( "2.\"3A%2BB=80\"
\n" ); document.write( "Now you have two equations in two unknowns.
\n" ); document.write( "Subtract eq. 1 from eq. 2 to eliminate B and solve for A.
\n" ); document.write( "Then go back to either equation and solve for A.
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