document.write( "Question 383323: Beer A is 6% alcohol, Beer B is 2% alcohol.
\n" );
document.write( "how many liters of beer A should be mixed in order to get 50 liters of mixture that is 3.2% alcohol.\r
\n" );
document.write( "\n" );
document.write( "solution A + B = 50 liter
\n" );
document.write( " 6%+2% = 3.2% alcohol
\n" );
document.write( " .06 + .02= 3.2
\n" );
document.write( " \r
\n" );
document.write( "\n" );
document.write( "I am stuck on this calculation, need to get one of the variables alone...like A but am not sure where to go from this point... \n" );
document.write( "
Algebra.Com's Answer #271615 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Let A be the amount of beer A, B the amount of beer B. \n" ); document.write( "1. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2. \n" ); document.write( "Now you have two equations in two unknowns. \n" ); document.write( "Subtract eq. 1 from eq. 2 to eliminate B and solve for A. \n" ); document.write( "Then go back to either equation and solve for A. \n" ); document.write( " \n" ); document.write( " |