document.write( "Question 383530: 8^2x-1=90 I need this to the nearest thousandths \n" ); document.write( "
Algebra.Com's Answer #271572 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x, to the nearest thousandth.
\n" ); document.write( "\"8%5E%282x-1%29+=+90\" Is this right? Take the log of both sides.
\n" ); document.write( "\"Log%288%5E%282x%29%29+=+Log%2890%29\" Apply the power rule to the left side.
\n" ); document.write( "\"2x%2ALog%288%29+=+Log%2890%29\" Divide both sides by \"Log%288%29\"
\n" ); document.write( "\"2x+=+Log%2890%29%2FLog%288%29\" Evaluate the right side.
\n" ); document.write( "\"2x+=+1.0269\" Divide both sides by 2.
\n" ); document.write( "\"x+=+0.513\"
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