document.write( "Question 383496: The recovery rate of cattle from a certain disease is 0.22. If 200 cattle are affected what is the probability that at least 51 will recover? \n" ); document.write( "

Algebra.Com's Answer #271528 by robertb(5830) $\"\"$ $\"About$

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Use the normal approximation to the binomial distribution:
\n" ); document.write( "n = 200, p = 0.22, q = 0.78, $\"mu+=+np+=+44\"$ , and $\"sigma+=+sqrt%28npq%29+=+sqrt%28200%2A0.22%2A0.78%29+=+5.85833\"$ . Then $\"P%28X+%3E=+50.5%29+=+P%28%28X+-+mu%29%2Fsigma+%3E=+%2850.5+-+44%29%2F5.85833+=+1.1%29\"$ . Thus $\"P%28X+%3E=+50.5%29+=+P%28Z+%3E=+1.1%29+=+0.1357\"$ . \n" ); document.write( "

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