document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=383331>Question 383331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation in the form of y=mx+b through (2,2), perpendicular to y=3x+4. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271511 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271511\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the equation in the form of y=mx+b through (2,2), perpendicular to y=3x+4.<BR>\n" );
document.write( " Sol'n:<BR>\n" );
document.write( "  from the equation: y=3x+4, the slope(m) is already known which is 3,<BR>\n" );
document.write( "for the perpendicular lines:<BR>\n" );
document.write( " (m1)(m2)= -1, where m1 and m2 are the slope of two perpendicular lines,<BR>\n" );
document.write( "  if we take m1 = 3<BR>\n" );
document.write( " so, m2= -1/3<BR>\n" );
document.write( "then, at pt. (2,2):<BR>\n" );
document.write( " y-y1 = m(x-x1)<BR>\n" );
document.write( " y-2=-(x-2)/3<BR>\n" );
document.write( " 3(y-2)=-(x-2)<BR>\n" );
document.write( " 3y-6=-x+2<BR>\n" );
document.write( " x+3y-8=0 ----answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );