document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=383466>Question 383466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can anyone explain how to solve this problem:  24x + 5= 12x + 41. I need to see the work so I can understand the process. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271497 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24x + 5= 12x + 41<BR>\n" );
document.write( "...<BR>\n" );
document.write( "we have to bring the terms on one side & the constants to the other side of the equal sign<BR>\n" );
document.write( "shift 5 to the right side<BR>\n" );
document.write( "add -5 to both sides<BR>\n" );
document.write( "24x+5-5 = 12x+41-5<BR>\n" );
document.write( "24x=12x+36<BR>\n" );
document.write( "..<BR>\n" );
document.write( "shift 12x to the left side<BR>\n" );
document.write( "add -12x to both sides<BR>\n" );
document.write( "24x-12x=12x-12x+36<BR>\n" );
document.write( "12x=36<BR>\n" );
document.write( "..<BR>\n" );
document.write( "divide by 12 to keep only x on the left side<BR>\n" );
document.write( "12x/12 = 36/12<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28highlight%28x=3%29%29 ALIGN=MIDDLE  ALT=\"%28highlight%28x=3%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );