document.write( "Question 383447: A boat traveling at 10 mph can go 20 miles against a current in the same time it can go 60 miles with the current. How fast is the current of this river? \n" ); document.write( "
Algebra.Com's Answer #271480 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let current rate = xmph \n" ); document.write( "rate upstream = 10-x \n" ); document.write( ".. \n" ); document.write( "time upstream = 20/(10-x) \n" ); document.write( ".... \n" ); document.write( "time downstream = 60/(10+x) \n" ); document.write( ".. \n" ); document.write( "time downstream = time upstream \n" ); document.write( "20/(10-x)= 60/(10+x) \n" ); document.write( "cross multiply \n" ); document.write( "20(10+x)=60(10-x) \n" ); document.write( "200+20x=600-60x \n" ); document.write( "80x=400 \n" ); document.write( "/80 \n" ); document.write( "x=400/80 \n" ); document.write( "x= 5 mph \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |