document.write( "Question 383320: I am so confused with this. Please help.\r
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document.write( "Graph y=log(base 3)(x+2)+1 \n" );
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Algebra.Com's Answer #271441 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Graph y=log3(x+2)+1\r \n" ); document.write( "\n" ); document.write( "---- \n" ); document.write( "Identify the Domain: \n" ); document.write( "Solve x+2 > 0 \n" ); document.write( "x > -2 is the domain \n" ); document.write( "----- \n" ); document.write( "y = [log3(x+2)] + 1 \n" ); document.write( "---------------------------------- \n" ); document.write( "Vertical asymptote at x = -2 \n" ); document.write( "-------- \n" ); document.write( "x-intercept: \n" ); document.write( "Let y = 0 \n" ); document.write( "Then [log3(x+2)] + 1 = 0 \n" ); document.write( "--- \n" ); document.write( "[log3(x+2)] = -1 \n" ); document.write( "--- \n" ); document.write( "x+2 = 3^-1 \n" ); document.write( "x+2 = 1/3 \n" ); document.write( "x = -5/3 \n" ); document.write( "---- \n" ); document.write( "Plot the asymptote and the point (-5/3,0) \n" ); document.write( "---------- \n" ); document.write( "Sketch the log curve using those two reference facts. \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( "--------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |