document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=383330>Question 383330</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many years does it take a 25 year old to be 3 times the age of a 13 year old </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271439 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A' age= 13 years<BR>\n" );
document.write( "B's age = 25 years<BR>\n" );
document.write( "...<BR>\n" );
document.write( "After x years <BR>\n" );
document.write( "A= x+13<BR>\n" );
document.write( "B= x+25<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+25 = 2(x+13)<BR>\n" );
document.write( "x+25 = 2x+26<BR>\n" );
document.write( "2x-x= 26-25<BR>\n" );
document.write( "x= 1<BR>\n" );
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document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );