document.write( "Question 383262: the perimeter of a rectangle is 36 yd. The width is 18 yd less than twice the length. find the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #271420 by mandi08(1)\"\" \"About 
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Perimeter = 2W + 2L
\n" ); document.write( "36 = 2W + 2L\r
\n" ); document.write( "\n" ); document.write( "We will use L as our variable. \r
\n" ); document.write( "\n" ); document.write( "L is the length; the width is 18 less than twice the length, therefore (2L - 18).\r
\n" ); document.write( "\n" ); document.write( "Plug this in to the perimeter equation and you get:
\n" ); document.write( "36 = 2(2L-18) + 2(L)
\n" ); document.write( "36 = 4L - 36 + 2L
\n" ); document.write( "72 = 4L + 2L
\n" ); document.write( "72 = 6L
\n" ); document.write( "L=12\r
\n" ); document.write( "\n" ); document.write( "Now we know the length, so we need to figure out the width. The equation to find the width is:
\n" ); document.write( "W = 2L - 18
\n" ); document.write( "W = 2(12) - 18
\n" ); document.write( "W = 24 - 18
\n" ); document.write( "W = 6
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