document.write( "Question 383221: Hi, Please can somebody help with this,\r
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document.write( "The base radius r cm of a right-circular cone increases at 2 cm s^-1 and its height h cm at 3 cm s^-1. Show that the rate of increase in its volume V = 1/3 pi r^2h when r = 5 and h = 15 is 125 pi cm^3 s^-1.
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Algebra.Com's Answer #271390 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! We have\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h and r are both functions in terms of time, t. We can take dV/dt by the product rule:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At this instant, we have \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |