document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=383202>Question 383202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't see my catagory. It is about permutations. My book is not giving me clear answers. I need to find the number of permutations for: 1,3,5? and another is: 7P3? Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271386 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The set of permutations of {1,3,5} is simply the set of all possible ways of arranging {1,3,5}. These are\r<BR>\n" );
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document.write( "{1,3,5}, {1,5,3}, {3,1,5}, {3,5,1}, {5,1,3}, {5,3,1}\r<BR>\n" );
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document.write( "Since there are 6 items in this collection, this means that there are 6 permutations.\r<BR>\n" );
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document.write( "A quick way of computing this is to simply calculate 3! to get 3! = 3*2*1 = 6\r<BR>\n" );
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document.write( "Recall that \r<BR>\n" );
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document.write( "n P r = (n!)/(n-r)!\r<BR>\n" );
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document.write( "So in this case, n = 7 and r = 3, which means that \r<BR>\n" );
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document.write( "7 P 3 = (7!)/(7-3)! = (7*6*5*4!)/(4!) = 7*6*5 = 210\r<BR>\n" );
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document.write( "So 7 P 3 = 210 </SPAN>\n" );
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