document.write( "Question 383091: Given $\"f%28x%29=%28x-3%29%2F%28x-1%29\"$ and $\"g%28x%29=%28x-4%29%2F%28x-2%29\"$
\n" ); document.write( "Find (f o g)(x) \n" ); document.write( "

Algebra.Com's Answer #271376 by Jk22(389) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28fog%29%28x%29=f%28g%28x%29%29=f%28y%29=%28y-3%29%2F%28y-1%29\"$ , with substitution $\"y=g%28x%29=%28x-4%29%2F%28x-2%29\"$
\n" ); document.write( "
\n" ); document.write( " $\"%28%28x-4%29%2F%28x-2%29-3%29%2F%28%28x-4%29%2F%28x-2%29-1%29\"$ | put on same denominator up and down
\n" ); document.write( "
\n" ); document.write( " $\"+%28%28x-4-3%2A%28x-2%29%29%2F%28x-2%29%29%2F%28%28x-4-%28x-2%29%29%2F%28x-2%29%29\"$ |collect term in fractions
\n" ); document.write( "
\n" ); document.write( " $\"%28%28-2x%2B2%29%2F%28x-2%29%29%2F%28%28-2%29%2F%28x-2%29%29\"$ |use 1/(a/b)=b/a to \"take up\" the down fraction
\n" ); document.write( "
\n" ); document.write( " $\"%28-2x%2B2%29%2F%28x-2%29%2A%28x-2%29%2F%28-2%29\"$ |simplify terms up and down\r
\n" ); document.write( "\n" ); document.write( " $\"x-1\"$ \n" ); document.write( "

\n" );