document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=382936>Question 382936</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x: log x + (log x + 21)=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271269 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x: log x + (log x + 21)=2\r<BR>\n" );
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document.write( "log x + (log x + 21) = 2<BR>\n" );
document.write( "thinking you meant log x + 21 and not log (x + 21), sorry if this was not the case<BR>\n" );
document.write( "2log x + 21 = 2<BR>\n" );
document.write( "2log x = -19<BR>\n" );
document.write( "log x = -19/2 = -9.5<BR>\n" );
document.write( "logarithmic rule: if logb x = y, then b^y = x<BR>\n" );
document.write( "assuming base is 10<BR>\n" );
document.write( "10^(-9.5) = x<BR>\n" );
document.write( "3.162278 * 10^(-10) rounded places after the decimal point to 6 places<BR>\n" );
document.write( " </SPAN>\n" );
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