document.write( "Question 382856: in rhombus ABCD, AB=14 and AC=20. Find the area of the rhombus to the nearest tenth \n" ); document.write( "
Algebra.Com's Answer #271244 by richard1234(7193)\"\" \"About 
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Since AB = 14, then BC and all other side lengths are 14. The diagonal AC is 20, so I'll find the area of ABC using Heron's formula:\r
\n" ); document.write( "\n" ); document.write( "A(ABC) = \"sqrt%28%2824%29%284%29%2810%29%2810%29%29+=+10+sqrt%2896%29+=+40+sqrt%286%29\"\r
\n" ); document.write( "\n" ); document.write( "However, ABC is only half the area of the rhombus, so the area of the rhombus is \"80+sqrt%286%29\" = 196.0 (to nearest tenth)
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