document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=382803>Question 382803</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the length of the hypotenuse of a right triangle if one leg is 12 inches and the other leg is 5 inches less then the hypotenus </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271221 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pythagoras theorem <BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "a= leg1<BR>\n" );
document.write( "b=leg2<BR>\n" );
document.write( "c= hypotenuse<BR>\n" );
document.write( "...<BR>\n" );
document.write( "5^2+12^2=hypotenuse^2<BR>\n" );
document.write( "25+144=h^2<BR>\n" );
document.write( "169=h^2<BR>\n" );
document.write( "square root on both sides<BR>\n" );
document.write( "13 = h<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Hypotenuse = 13 inches<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );