document.write( "Question 382816: the product of two consecutive integers is 11 more than their sum. find the intergers \n" ); document.write( "
Algebra.Com's Answer #271218 by mananth(16946)\"\" \"About 
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let the integers be x & x+1
\n" ); document.write( "Product = x(x+1)
\n" ); document.write( "...
\n" ); document.write( "x+x+1+11
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\n" ); document.write( "x(x+1)=x+x+1+11
\n" ); document.write( "x^2+x=2x+12
\n" ); document.write( "-2x -2x
\n" ); document.write( "x^2-2x+x=12
\n" ); document.write( "x^2-x=12
\n" ); document.write( "-12 -12
\n" ); document.write( "x^2-x-12=0
\n" ); document.write( "(x-4)(x+3)=12
\n" ); document.write( "x= 4 OR -3
\n" ); document.write( "...
\n" ); document.write( "4,5 OR -3,-2
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\n" ); document.write( "m.ananth@hotmail.ca
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