document.write( "Question 382816: the product of two consecutive integers is 11 more than their sum. find the intergers \n" ); document.write( "
Algebra.Com's Answer #271218 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the integers be x & x+1 \n" ); document.write( "Product = x(x+1) \n" ); document.write( "... \n" ); document.write( "x+x+1+11 \n" ); document.write( "... \n" ); document.write( "x(x+1)=x+x+1+11 \n" ); document.write( "x^2+x=2x+12 \n" ); document.write( "-2x -2x \n" ); document.write( "x^2-2x+x=12 \n" ); document.write( "x^2-x=12 \n" ); document.write( "-12 -12 \n" ); document.write( "x^2-x-12=0 \n" ); document.write( "(x-4)(x+3)=12 \n" ); document.write( "x= 4 OR -3 \n" ); document.write( "... \n" ); document.write( "4,5 OR -3,-2 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |