document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=382797>Question 382797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey I need your help! PLEASE HELP!<BR>\n" );
document.write( "A rectangle is twice as long as it is wide and has a diagonal of length 25 cm. what are its dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271214 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide and has a diagonal of length 25 cm. what are its dimensions<BR>\n" );
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document.write( "Apply Pythagorean theorem:<BR>\n" );
document.write( "Let w = width<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2w = length<BR>\n" );
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document.write( "w^2 + (2w)^2 = 25^2\r<BR>\n" );
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document.write( "w^2 + 4w^2 = 625<BR>\n" );
document.write( "5w^2 = 625<BR>\n" );
document.write( "w^2 = 105<BR>\n" );
document.write( "w = sqrt(105)<BR>\n" );
document.write( "w = 10.25 cm (width)<BR>\n" );
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document.write( "length:<BR>\n" );
document.write( "2w = 2(10.25) = 20.5 cm<BR>\n" );
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