document.write( "Question 382830: 5 years ago, my brother was exactly twice the age i was then. And in eight year's time, the combined age of two of us will be 50. How old do u think i am? \n" ); document.write( "
Algebra.Com's Answer #271206 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let my age now be x years \n" ); document.write( ". \n" ); document.write( "5 years ago my age = x-5 years. \n" ); document.write( "brother's age = 2(x-5) years. \n" ); document.write( ".. \n" ); document.write( "After 8 years \n" ); document.write( "my age = (x-5) + 13 \n" ); document.write( "brother's age = 2(x-5)+13 \n" ); document.write( ".. \n" ); document.write( "(x-5)+13 +2(x-5)+13=50 \n" ); document.write( "x-5 +13 +2x-10+13=50 \n" ); document.write( "x+2x+13-10+13-5=50 \n" ); document.write( "3x+11=50 \n" ); document.write( "-11 -11 \n" ); document.write( "3x= 50-11 \n" ); document.write( "3x=39 \n" ); document.write( "/3 \n" ); document.write( "x= 39/3 \n" ); document.write( "x= 13 years. my age now. \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |