document.write( "Question 382830: 5 years ago, my brother was exactly twice the age i was then. And in eight year's time, the combined age of two of us will be 50. How old do u think i am? \n" ); document.write( "
Algebra.Com's Answer #271206 by mananth(16946)\"\" \"About 
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let my age now be x years
\n" ); document.write( ".
\n" ); document.write( "5 years ago my age = x-5 years.
\n" ); document.write( "brother's age = 2(x-5) years.
\n" ); document.write( "..
\n" ); document.write( "After 8 years
\n" ); document.write( "my age = (x-5) + 13
\n" ); document.write( "brother's age = 2(x-5)+13
\n" ); document.write( "..
\n" ); document.write( "(x-5)+13 +2(x-5)+13=50
\n" ); document.write( "x-5 +13 +2x-10+13=50
\n" ); document.write( "x+2x+13-10+13-5=50
\n" ); document.write( "3x+11=50
\n" ); document.write( "-11 -11
\n" ); document.write( "3x= 50-11
\n" ); document.write( "3x=39
\n" ); document.write( "/3
\n" ); document.write( "x= 39/3
\n" ); document.write( "x= 13 years. my age now.
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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