document.write( "Question 382740: 2 marbles are drawn without replacement from a box of 3 white 2 green 2 red and 1 blue marble. find the probablity
\n" ); document.write( "1. the second marble is blue given the first marble is red. so i got (rd) 1/4 and (blue) 1/7 so 1/4*1/7= 1/28 but my choices are 1/8 b. 1/4 c.1/7 or d. 2/7 so I am not sure what I am doing wrong.
\n" ); document.write( "2. the second marble is blue given the first marble is blue and I got 0 since there is only 1 marble is that correct? \n" ); document.write( "
Algebra.Com's Answer #271163 by stanbon(75887)\"\" \"About 
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2 marbles are drawn without replacement from a box of 3 white 2 green 2 red and 1 blue marble. find the probablity
\n" ); document.write( "1. the second marble is blue given the first marble is red. so i got (rd) 1/4 and (blue) 1/7 so 1/4*1/7= 1/28 but my choices are 1/8 b. 1/4 c.1/7 or d. 2/7 so I am not sure what I am doing wrong.
\n" ); document.write( "Ans:P(2nd is blue given the 1st is red) = 2/7
\n" ); document.write( "Comment: They don't want the probability of the 2 draw sequence only
\n" ); document.write( "the probability getting a blue after a red has been drawn.
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\n" ); document.write( "2. the second marble is blue given the first marble is blue and I got 0 since there is only 1 marble is that correct?
\n" ); document.write( "Ans: CORRECT
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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