document.write( "Question 382629: How far will a rubber ball fall in 10 seconds? \n" ); document.write( "
Algebra.Com's Answer #271147 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
On Earth, the position of a ball in free-fall (ignoring air resistance) is modeled by\r
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\n" ); document.write( "\n" ); document.write( "\"X+=+%281%2F2%29at%5E2+%2B+vt+%2B+x\",\r
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\n" ); document.write( "\n" ); document.write( "where a = -9.81 m/(s^2), v = the original velocity, x is the original x position, and t is time.\r
\n" ); document.write( "\n" ); document.write( "Assuming x = 0 m, v = 0 m/s, we have\r
\n" ); document.write( "\n" ); document.write( "X = (1/2)(-9.81 m/(s^2))(10 s)^2 = -490.5 m\r
\n" ); document.write( "\n" ); document.write( "Without air resistance, the ball would've fallen 490.5 meters. However I'm sure that it would've reached terminal velocity before then :)
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