document.write( "Question 41964: Assume that y varies directly as x. If y =4 when x = 1/2, find y when x =2 \n" ); document.write( "
Algebra.Com's Answer #27114 by mbarugel(146)\"\" \"About 
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\n" ); document.write( "If y varies directly as x, then when x is multiplied by a factor, y is multiplied by the same factor.\r
\n" ); document.write( "\n" ); document.write( "Now, how many times is the increase in x from 1/2 to 2? This is calculated as:\r
\n" ); document.write( "\n" ); document.write( "\"2%2F%281%2F2%29+=+2%2A2+=+4\"\r
\n" ); document.write( "\n" ); document.write( "Therefore, 2 is 4 times as much as 1/2.\r
\n" ); document.write( "\n" ); document.write( "We conclude that, since y = 4 when x = 1/2; then, when x = 2 (4 times as much as 1/2), then y must be 4 times as much as its original value (4). Therefore, when x = 2, y = 4*4 = 16.\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps!
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