document.write( "Question 40998: Decreasing cube. Each of the three dimensions of a cube with a volume of y to the third power cubic centimeters is decreased by a whole number of centimeters. If the new volume is y-cubed - 13 y-squared + 54y - 72 cubic centimeters and the new width is y - 6 centimeters, then what are the new length and height? \n" ); document.write( "
Algebra.Com's Answer #27108 by psbhowmick(878)\"\" \"About 
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New volume = \"y%5E3-13y%5E2%2B54y-72\" cc.
\n" ); document.write( "Since (y - 6) cm is the new width, so it must be a factor of the new volume.
\n" ); document.write( "So, we will write \"y%5E3-13y%5E2%2B54y-72\" in such a way that (y - 6) may be taken common.\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E3-13y%5E2%2B54y-72\"
\n" ); document.write( "= \"y%5E3-6y%5E2-7y%5E2%2B42y%2B12y-72\"
\n" ); document.write( "= \"y%5E2%28y-6%29-7y%28y-6%29%2B12%28y-6%29\"
\n" ); document.write( "= \"%28y-6%29%28y%5E2-7y%2B12%29\"
\n" ); document.write( "= \"%28y-6%29%28y%5E2-3y-4y%2B12%29\"
\n" ); document.write( "= \"%28y-6%29%28y%28y-3%29-4%28y-3%29%29\"
\n" ); document.write( "= \"%28y-6%29%28y-3%29%28y-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "So clearly (y-3) cm and (y-4) cm are the new length and height respectively.\r
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\n" ); document.write( "\n" ); document.write( "[N.B.: (y-3) > (y-4); so (y-3) is length being the longest side]
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