document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=382595>Question 382595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Line AB is perpendicular to Line BN in the diagram at the right. What are the coordinates of Point N?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271074 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution 1: The coordinates of N are (x, 0).  Use the Pythagorean Theorem.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28BA%29%5E2+%2B+%28BN%29%5E2+=+%28AN%29%5E2 ALIGN=MIDDLE  ALT=\"%28BA%29%5E2+%2B+%28BN%29%5E2+=+%28AN%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283-0%29%5E2+%2B+%284-0%29%5E2+%2B+%283-x%29%5E2+%2B+%284-0%29%5E2+=+%28x-0%29%5E2+%2B+%280-0%29%5E2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9+%2B+16+%2B+9-6x%2B+x%5E2+%2B+16+=+x%5E2 ALIGN=MIDDLE  ALT=\"9+%2B+16+%2B+9-6x%2B+x%5E2+%2B+16+=+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >;<BR>\n" );
document.write( "50 - 6x = 0;<BR>\n" );
document.write( "50 = 6x;<BR>\n" );
document.write( "x = 25/3.\r<BR>\n" );
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document.write( "Solution2: Slope of line AB  is 4/3.  Thus the slope of line BN must be the negative reciprocal, or -3/4.<BR>\n" );
document.write( "Hence <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284-0%29%2F%283-x%29+=+-3%2F4 ALIGN=MIDDLE  ALT=\"%284-0%29%2F%283-x%29+=+-3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or 16 = -9 + 3x, or 25 = 3x, or x = 25/3. </SPAN>\n" );
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