document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=382470>Question 382470</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need to know how to do somethings such as i have an 85% alcohol solution and a 50%alcohol solution and i need a 65% solution. and i need 55 liters all together. how many liters of each do i need? i have the eqautions      \r<BR>\n" );
document.write( "\n" );
document.write( "x=how many liters of 85% <BR>\n" );
document.write( "y=how many liters of 50%\r<BR>\n" );
document.write( "\n" );
document.write( "i have x+y=55 (liters)<BR>\n" );
document.write( "and i have .85x+.50y= .65<BR>\n" );
document.write( " please reply as soon as possible, thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271046 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=how many liters of 85% <BR>\n" );
document.write( "y=how many liters of 50%<BR>\n" );
document.write( "-------------------------------- <BR>\n" );
document.write( "i have x+y=55 (liters)<BR>\n" );
document.write( "and i have .85x+.50y= .65*55<BR>\n" );
document.write( "------------------------------<BR>\n" );
document.write( "Multiply thru the 1st by 85 and the 2nd by 100 to get:<BR>\n" );
document.write( "85x + 85y = 85*55<BR>\n" );
document.write( "85x + 50y = 65*55<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Subtract the 2nd from the 1st and solve for \"y\":<BR>\n" );
document.write( "35y = 20*55<BR>\n" );
document.write( "y = 31.43 liters (amt. of 50% solution needed in the mixture)<BR>\n" );
document.write( "Since x + y = 55, x = 55-31.43 = 23.57 liters (amt of 85% needed in the mix)<BR>\n" );
document.write( "===========================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );