document.write( "Question 382415: a bag contains 6 cherry 3 orange and 2 lemon candies you reach in and take 3 pieces of candy at random find the probablity that you have all orange candies. I got 0.7272 not sure if that is right.
\n" ); document.write( "B. find the proability that you have 2 cherry and 1 lemon.
\n" ); document.write( "I also got .7272 for this.
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Algebra.Com's Answer #271026 by jim_thompson5910(35256)\"\" \"About 
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There are 6+3+2 = 11 candies total\r
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\n" ); document.write( "\n" ); document.write( "There are 11 C 3 = 165 different ways to select 3 candies (where order doesn't matter)\r
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\n" ); document.write( "\n" ); document.write( "Since there is only one way to choose 3 orange candies (3 C 3 = 1), this means that the probability is \"1%2F165=0.0060606060606\" which rounds to 0.006\r
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\n" ); document.write( "\n" ); document.write( "Again, there are 11 C 3 = 165 different ways to select 3 candies. \r
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\n" ); document.write( "\n" ); document.write( "There are 6 C 2 = 15 different ways to select 2 cherry candies and 2 C 1 = 2 different ways to select a single lemon candy.\r
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\n" ); document.write( "\n" ); document.write( "So there are 15*2 = 30 different ways to select 2 cherries and a lemon.\r
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\n" ); document.write( "\n" ); document.write( "So the probability is \"30%2F165=2%2F11=0.18181818\"
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