document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=382335>Question 382335</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with these two homework problems. I have worked out both of them and keep getting them incorrect.\r<BR>\n" );
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document.write( "The distribution of actual weight of 8 oz. cheese is normal mean with 8.1 oz. and standard deviation of 0.1 oz. \r<BR>\n" );
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document.write( "1. If a sample of five cheeses is selected, what is the probability their weight is less than 8 oz?\r<BR>\n" );
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document.write( "2. There is only a 5% chance that the five cheeses average age will be below?\r<BR>\n" );
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document.write( "For #1 I answered 0.9873. I did 8.1-8/(.1/sqrt5))<BR>\n" );
document.write( "For #2 I answered 8.08 ounces.\r<BR>\n" );
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document.write( "Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271006 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distribution of actual weight of 8 oz. cheese is normal mean with 8.1 oz. and standard deviation of 0.1 oz. <BR>\n" );
document.write( "1. If a sample of five cheeses is selected, what is the probability their weight is less than 8 oz? <BR>\n" );
document.write( "2. There is only a 5% chance that the five cheeses average age will be below?<BR>\n" );
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document.write( "For #1 t(8) = (8-8.1)/(.1/sqrt5)) = -2.2361<BR>\n" );
document.write( "P(x/bar < 8) = P(t<-2.2361 when df=4) = 0.0445<BR>\n" );
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document.write( "For #2 I answered 8.08 ounces.<BR>\n" );
document.write( "The t-value with a left tail of 5% when df=4 is -2.1318<BR>\n" );
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document.write( "The corresponding average weight is -2.1318*0.1 + 8.1 = 7.89 oz.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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