document.write( "Question 5324: could someone help me factor this. I'm horrible with factoring!
\n" ); document.write( "x^2-12x+27\r
\n" ); document.write( "\n" ); document.write( "( x )( x )
\n" ); document.write( "-12x 1,12 2,6 3,4 \r
\n" ); document.write( "\n" ); document.write( "27 1,27 3,9
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Algebra.Com's Answer #2710 by arunpaul(104)\"\" \"About 
You can put this solution on YOUR website!
x^2-12x+27
\n" ); document.write( "or x^2-9x-3x+27\r
\n" ); document.write( "\n" ); document.write( "factor in such afashion that the addition will be = -12 and multiplication will be =+27
\n" ); document.write( "and then the two number willbe -9 and -3\r
\n" ); document.write( "\n" ); document.write( "so the above equation will be
\n" ); document.write( "x(x-9)-3(x-9)
\n" ); document.write( "or the above equation will be
\n" ); document.write( "(x-3)(x-9) (ans)
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