document.write( "Question 382320: Find log (1/2)+log(2/3)+log(3/4)+log(4/5)+log(5/6+log(6/7)....log(98/98)+log(99/100) \n" ); document.write( "
Algebra.Com's Answer #270989 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find log (1/2)+log(2/3)+log(3/4)+log(4/5)+log(5/6+log(6/7)....log(98/98)+log(99/100) \n" ); document.write( "---- \n" ); document.write( "Fact: loga(b) = logc(b)/logc(a) \n" ); document.write( "This is the \"Change of Base Law\". \n" ); document.write( "----- \n" ); document.write( "Using that over and over and over agin on you problem \n" ); document.write( "you will see that everything cancels except \n" ); document.write( "log(1)/log(100) \n" ); document.write( "-------------------------------- \n" ); document.write( "= 0/2 = 0 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |