document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=382209>Question 382209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A beverage wholesaler wants to create a new punch. He will mix fruite juice worth $3 a gallon and rum worth $8 a gallon. He wants to obtain 145 gallons worth of punch worth $5 a gallon. How much of each beverage should he use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270978 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK<BR>\n" );
document.write( "Let x=amount of rum needed<BR>\n" );
document.write( "Then 145-x=amount of fruit juice needed\r<BR>\n" );
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document.write( "Now we know that the total value of the rum and fruit juice before they are mixed together is equal to the total value of the final mixture.\r<BR>\n" );
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document.write( "So: ($ understood)<BR>\n" );
document.write( "8x+3(145-x)=5*145<BR>\n" );
document.write( "8x+435-3x=725 subtract 435 from each side and collect like terms<BR>\n" );
document.write( "5x=290<BR>\n" );
document.write( "x=58 gal-----------------------amount of rum needed<BR>\n" );
document.write( "145-58=87 gal----amount of fruit juice needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "8*58+3*87=5*145<BR>\n" );
document.write( "464+261=725<BR>\n" );
document.write( "725=725\r<BR>\n" );
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document.write( "Hope this helps--ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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