document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41941>Question 41941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In three years, Chad will be three times my present age. I will then be half as old as he. How old am I?\r<BR>\n" );
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document.write( "I think it should be set up like this: 3x+3=1/2c<BR>\n" );
document.write( "\"x\" for present age, \"c\" for chad's age<BR>\n" );
document.write( "i know this can't be right because i can't get an answer that makes since. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27093 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When you do age problems, always set up the variables NOW...<BR>\n" );
document.write( "Let x be your age now and c be Chad's age now.  Thus<BR>\n" );
document.write( "c + 3 = 3x and<BR>\n" );
document.write( "x + 3 = (1/2)(c + 3)<BR>\n" );
document.write( "now double the second equation and substitute and we get<BR>\n" );
document.write( "2(x + 3) = c + 3 so that<BR>\n" );
document.write( "2(x + 3) = 3x<BR>\n" );
document.write( "2x + 6 = 3x<BR>\n" );
document.write( "x = 6<BR>\n" );
document.write( "c = 15 </SPAN>\n" );
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