document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41864>Question 41864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> speed of a dropped object.  If we neglect the resistnace of air, the (downward) speed of an object t seconds after being dropped is given by v=32t feet per second.  How many seconds does it take an object to reach a downward speed of 100 miles per hour?  recall that there are 5280 feet in one mile, since you will need to express 100 mph in feet per second.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27092 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay...we can convert mph to fps via the relationship<BR>\n" );
document.write( "60 miles per hour = 88 feet per second so that<BR>\n" );
document.write( "100 miles per hour = 146 2/3 feet per second.<BR>\n" );
document.write( "Thus we solve for t and get<BR>\n" );
document.write( "t = v/32<BR>\n" );
document.write( "t = (146 2/3) / 32<BR>\n" );
document.write( "t = 55/12 sec = 4 7/12 sec </SPAN>\n" );
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