document.write( "Question 382115: 18)Solve the system of equations by the addition method.\r
\n" ); document.write( "\n" ); document.write( "x/4-y/12=-1\r
\n" ); document.write( "\n" ); document.write( "x/3+y/9=-2\r
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Algebra.Com's Answer #270914 by mananth(16946)\"\" \"About 
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x/4-y/12=-1
\n" ); document.write( "multiply by12
\n" ); document.write( "3x-y=-12.................1\r
\n" ); document.write( "\n" ); document.write( "x/3+y/9=-2
\n" ); document.write( "multiply by 9
\n" ); document.write( "3x+y = -18................2
\n" ); document.write( "...
\n" ); document.write( "add 1 & 2
\n" ); document.write( "6x=-12-18
\n" ); document.write( "6x=-30
\n" ); document.write( "/6
\n" ); document.write( "\"%28highlight%28x=-5%29%29\"
\n" ); document.write( "..
\n" ); document.write( "plug value of x in 1
\n" ); document.write( "3*-5-y=-12
\n" ); document.write( "-15-y=-12
\n" ); document.write( "-15+12=y
\n" ); document.write( "\"%28highlight%28y=-3%29%29\"
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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