document.write( "Question 382048: verify: sin4x+2sin2xcos2x+cos4x=tanxcotx \n" ); document.write( "
Algebra.Com's Answer #270863 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
I hope you meant \"sin%5E4+%28x%29\" instead of \"sin+%284x%29\". I first thought it was the latter interpretation which is not true for all x, but then noticed that the first interpretation yielded a true identity, which I'll explain below:\r
\n" ); document.write( "\n" ); document.write( "First note that tan x cot x = 1 (given that tan x and cot x are nonzero). The expression\r
\n" ); document.write( "\n" ); document.write( "\"sin%5E4+%28x%29+%2B+2+sin%5E2+%28x%29+cos%5E2+%28x%29+%2B+cos%5E4+%28x%29\" factors to\r
\n" ); document.write( "\n" ); document.write( "\"%28sin%5E2+%28x%29+%2B+cos%5E2+%28x%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Since \"sin%5E2+%28x%29+%2B+cos%5E2+%28x%29+=+1\", and \"1%5E2+=+1\", both sides are equal to 1, and we are done.\r
\n" ); document.write( "\n" ); document.write( "Next time, I would encourage you to put the caret (\"^\") sign to denote an exponent, to make the question less ambiguous.
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