document.write( "Question 381977: Bill and Roger want to race. Bill runs an average of 12 mph and Roger runs an average of 10 mph. To 'even things up' Bill lets Roger have a head start of .15 hour. How long before Bill catches up?\r
\n" ); document.write( "\n" ); document.write( "this is what I did:
\n" ); document.write( "12(x)=10(.15)
\n" ); document.write( "x=.125
\n" ); document.write( "or 7.5 minutes\r
\n" ); document.write( "\n" ); document.write( "Is that correct?
\n" ); document.write( "I also came up with 45 minutes...
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Algebra.Com's Answer #270845 by mananth(16949)\"\" \"About 
You can put this solution on YOUR website!
Bill runs an average of 12 mph
\n" ); document.write( " Roger runs an average of 10 mph.
\n" ); document.write( "head start of .15 hour. for roger
\n" ); document.write( "..
\n" ); document.write( "make up speed for Bill is 12-10 = 2mph.
\n" ); document.write( "..
\n" ); document.write( "Roger has head start of 0.15 hour
\n" ); document.write( "so distance = 0.15 *10= 1.5 miles\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "t = d/r
\n" ); document.write( "1.5/2
\n" ); document.write( "=0.75 hours OR 45 minutes to catch up
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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