document.write( "Question 41815: I need your help\r
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document.write( "to solve for x\r
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document.write( "in the equation\r
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document.write( "3ln(2-x)=6\r
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document.write( "I tried to solve it but I'm not sure if my answer is correct\r
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document.write( "3ln(2-x)=6
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document.write( "ln2/lnx=2
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document.write( "ln2=2lnx
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document.write( "e^(2-x)=2
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document.write( "ln(2-x)=2
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document.write( "e^2=e^ln(x+5)
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document.write( "e^2-5=x \n" );
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Algebra.Com's Answer #27080 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! I need your help \n" ); document.write( "to solve for x \n" ); document.write( "in the equation \n" ); document.write( "3ln(2-x)=6.......OK\r \n" ); document.write( "\n" ); document.write( "I tried to solve it but I'm not sure if my answer is correct \n" ); document.write( "3ln(2-x)=6............OK\r \n" ); document.write( "\n" ); document.write( "ln2/lnx=2....NO..NO...NO..THERE IS NO SUCH FORMULA..LN(X/Y)=LN(X)-LN(Y).. \n" ); document.write( "BUT LN(X-Y) IS NOT EQUAL TO LN(X-Y) \n" ); document.write( "SO LN(2-X)=6/3=2 \n" ); document.write( "E^2=2-X \n" ); document.write( "X=2-E^2 \n" ); document.write( " |