document.write( "Question 381701: hello all, \r
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document.write( "I am taking grad level complex algebra and i will appreciate if anyone can help me with the following problem:\r
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document.write( "Find the common greatest divisor between 3+4i and 4-3i \n" );
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Algebra.Com's Answer #270793 by Edwin McCravy(20067) You can put this solution on YOUR website! First a little background, which you may already be familiar with.\r\n" ); document.write( "\r\n" ); document.write( "[Since no complex integer can be said to be \"greater\" than another, nor\r\n" ); document.write( "the \"greatest\" in a set, one might think it should be meaningless to speak of\r\n" ); document.write( "a \"greatest\" common divisor. However not all common divisors are divisible\r\n" ); document.write( "by all other common divisors. For instance ±1, ±i and 1+i are all common\r\n" ); document.write( "divisors of 2+2i and 3+3i. However ±1, ±i are not divisible by 1+i, athough\r\n" ); document.write( "1+i is divisble by them. We reserve the term \"greatest\" for a common divisor\r\n" ); document.write( "that is divisible by ALL common divisors. \"Greatest\" is still a misnomer,\r\n" ); document.write( "since none are really \"greater\" than any of the others, but we still use the\r\n" ); document.write( "term \"GCD\" to refer to any common divisor that is divisible by ALL common\r\n" ); document.write( "divisors.] \r\n" ); document.write( "\r\n" ); document.write( "Since there are 4 unit complex integers, ±1, ±i, there are 4 associate\r\n" ); document.write( "GCD's of any two complex integers. That is, if a+bi is a GCD of p+qi\r\n" ); document.write( "and r+si then all four of these are also GCDs of p+qi and r+si.\r\n" ); document.write( "\r\n" ); document.write( " 1(a+bi) = a+bi\r\n" ); document.write( "-1(a+bi) = -a-bi \r\n" ); document.write( " i(a+bi) = ai+bi² = ai+b(-1) = ai-b = -b+ai\r\n" ); document.write( "-i(a+bi) = -ai-bi² = -ai-b(-1) = -ai+b = b-ai \r\n" ); document.write( " \r\n" ); document.write( "To use the Euclidean algorithm, we begin by dividing one by the other until\r\n" ); document.write( "we get a remainder of 0.\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |