document.write( "Question 381637: How many liters of a 10% alcohol solution must be mixed with 20 liters of a 40% solution to get a 20% solution?
\n" ); document.write( "-Thankyou
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Algebra.Com's Answer #270690 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "Let x represent the amount of the 10% Solution,
\n" ); document.write( "then (20L +x) will be the amount of the final solution
\n" ); document.write( "Mixing to form the solution***
\n" ); document.write( " .10x + .40*20L = .20(x + 20L)
\n" ); document.write( "Solving for x
\n" ); document.write( " .20*20L = .10x
\n" ); document.write( " .20*20L/.10 = x
\n" ); document.write( " 40L = x, the amount of the 10% Solution\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " .10*40 + .40*20 = 4L + 8L = .20*60 = 12 \n" ); document.write( "
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