document.write( "Question 381611: Find three consecutive odd integers such that five times the middle integer equals 33 more than the sum of the first and the last. \n" ); document.write( "

Algebra.Com's Answer #270683 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( "Let x, (x+2) and (x+4) represent the three consecutive odd integers
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document.write( "Write as we Read***
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document.write( "5(x+2) = x + (x+4) + 33
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document.write( "solving for x
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document.write( "5x + 10 = 2x + 37
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document.write( "   3x = 27
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document.write( "    x = 9
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document.write( "the three consecutive odd integers are 9, 11, 13\r
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document.write( "CHECKING our Answer***
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document.write( "  45 = 9 + 13 + 33 
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