document.write( "Question 381559: 2x+3/x-1=10/X^2-1+2x-3/x+1 how do you solve this problem? thanks \n" ); document.write( "
Algebra.Com's Answer #270658 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(2x+3)/(x-1) = 10/(X^2-1)+(2x-3)/(x+1)
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\n" ); document.write( "Multiply thru by x^2-1 which equals (x-1)(x+1)
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\n" ); document.write( "(2x+3)(x+1) = 10 + (2x-3)(x-1)
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\n" ); document.write( "2x^2+5x+3 = 10 + 2x^2-5x +3
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\n" ); document.write( "10x = 10
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\n" ); document.write( "x = 1
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\n" ); document.write( "But x cannot = 1 as that would give you a zero in the denominator.
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\n" ); document.write( "Final answer: No solution
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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